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Velocity and acceleration vectors of Planar curves worksheet

Velocity and acceleration vectors of Planar curves worksheet
  • 1. Find the velocity vector of a particle whose equation of the motion is given as, x ( t ) = t 2 + 5 t 3 and y ( t ) = t 3 – t 5, 
    here, ‘t’ is representing the time variable. Calculate the velocity vector at t = 3?
    1. (141 , - 378 )
    2. ( 200 , 475 )
    3. ( - 378 , 141 )
    4. ( 339, 219 )
  • 2. Evaluate the acceleration vector for the particle whose equation of motion is given as, x ( t ) = t + 7 t 4, y ( t ) = 2 t + 3 t 2, At time t = 2?
    1. (997, - 5)
    2. (112 , 6)
    3. (244 , 5)
    4. (336, 6)
  • 3. Find the velocity vector of a particle whose equation is given as: 
     x ( t ) = t 4 + t 2,
    y ( t ) = 2 t + t,
    at point t = 1?
    1. (776 , 997)
    2. (6 , 3)
    3. (985, 120)
    4. (- 225, 219)
  • 4. Evaluate the acceleration vector for the particle whose equation of motion is given as,
    x ( t ) = t 3 + 3 t 3,
     y ( t ) = t + 4 t 3,
    At time t = 5?
    1. (4 , - 997 )
    2. (120 ,120)
    3. (- 56 , 667)
    4. (-120, 120)
  • 5. Find the velocity vector of a particle whose equation is given as: 
     x ( t ) = t 5 + 9 t
    y ( t ) = 7 t + t 2
    at point t = 5 ?
    1. (3134 ,17)
    2. (3134, 99)
    3. (3135 , 665)
    4. (339, 219)
  • 6. Evaluate the acceleration vector for the particle whose equation of motion is given as,
     x ( t ) = 3 t 4
     y ( t ) = 6 t + 3 t 7
    At time t = 1 ?
    1. (76 , 43)
    2. (27 , 36)
    3. (554 , 141)
    4. (36 , 27)
  • 7. Find the velocity vector of a particle whose equation is given as
     x ( t ) = t 1 + t 5
    y ( t ) = 5?
    at point t = 3?
    1. ( 0 , -663)
    2. (406, 0)
    3. (775, 331)
    4. (406, 77)
  • 8. Evaluate the acceleration vector for the particle whose equation of motion is given as,
     x ( t ) = 2 t 2 + 9
     y ( t ) = 2 t + t 2
    At time t = 177 ?
    1. (4 , 2)
    2. (9, 1)
    3. (9 , 9)
    4. (1, 1)
  • 9. Find the velocity vector of a particle whose equation is given as
     x ( t ) = 2997 t + t 2
    y ( t ) = 997 t
    at point t = 0 ?
    1. (255 , 599)
    2. (2997 , 997)
    3. (- 995 , 771)
    4. (995, 774)
  • 10. Evaluate the acceleration vector for the particle whose equation of motion is given as,
     x ( t ) = t 1099 + t
     y ( t ) = t + 4 t 2995
    At time t = 5?
    1. (0 , 0)
    2. (0, 77)
    3. (99 , 0)
    4. (44, 0)
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