In mathematics, x – coordinates values that present in the function is a Domain of a function and the entire y – coordinate values is The Range of a function. It is denoted by f (). In f (s), 's' is the value of domain of a function.
For example: (3, 4), (6, 4), (7, 13), (15, 25). In this example all x – coordinate values represent the domain of a function and all y – coordinate values represent the range of a function.
Algebra Functions are used to calculate the value of unknown variables in the equations. To represent unknown quantity in Algebra we have to assume variable which is a letter or symbol. And the group of Numbers, symbols, real numbers and Polynomials that express an operation is known as an algebraic expression.
In an algebra function we maintain the information that helps to understand Algebraic Equations.
In algebra, to calculate unknown value of functions in the form of p (i) = au2 + bu + c, we need to find the function variable 'u'.
First we construct a table for calculating the unknown variable and put the values like x, y, z, etc.
|
u |
P (u) = au2 + bu + c
|
|
x |
P (x) = ax2 + bx + c
|
|
y |
P (y) = ay2 + by + c
|
|
. . . |
. . . |
|
z |
P (z) = az2 + bz + c
|
Now we will apply this procedure in the equation. Consider the equation f (s) = s2 + 8s + 16 and the number 1, 3, 4 and 6 as 's' in the function.
Put the value of 's' into the equation of function f (s) = s2 + 8s + 16;
According to the equation, first Square s, add 8 * s and add 16 we will get f (s) as a result.
|
S |
F (s) = s2 + 8s + 16
|
F (s) |
|
1 |
F (1) = (1)2 + 8 * 1 + 16
|
25 |
|
3 |
F (3) = 9 + 8 * 3 + 16
|
49 |
|
4 |
F (4) = 16 + 8 * 4 + 16
|
64 |
|
6 |
F (6) = 36 + 8 * 6 + 16
|
108 |
This is how we can solve the algebra function.